下面的数学题谁会做?我女儿不会!【六年级】我又不会!急急急!对的给多悬赏!!今晚要答案!快速!

2024-12-30 20:31:44
推荐回答(6个)
回答1:

1.设鸡有X只,兔有Y只,那么可以得到两个方程X+Y=8 2X+4Y=28,让你女儿把这个方程组解出来就可以了
2.同上的思路
3.设三人间为X,双人间为Y,X+Y=9 3X+2Y=22,还是方程组
4.设3角的为X之,5角的为Y之,X+Y=80 单位换算:31元=310角 3X+5Y=310,还是方程组

下面的提都一样,都是用方程组就可以解决
1 教师为X,学生为Y,X+Y=100 5X+Y=200,解方程组
2 大油瓶为X,小油瓶为Y,X+Y=55 4X+Y=80
3 完整的为X,损坏的为Y,X+Y=250 20X-100Y=4400
都是用二元方程组解的,这个应该会吧,呵呵

好累啊,求给分

回答2:

这些题可以看成鸡兔同笼问题
解答方法一:一只鸡2只脚,一只兔4只脚。所以,假设全是鸡,那么一共有2*8=16只脚,而实际28只脚,相差的就是兔子多的脚=28-16=12,每只兔子多2只脚,所以兔子共有12/2=6,故鸡有8-6=2只。
方法二:解方程设鸡有X只,兔有就有8-X只,那么可以得到两个方程2X+4*(8-X)=28
X=2
其他题如法炮制,只要明确“鸡”和“兔”不同点即可。

回答3:

1.假设都是兔 8x4=32(只)鸡:(32-28)÷(4-2)=2(只)兔:8-2=6(只)
2.同上
3.假设都是3人间 双人间:(3x9-22)÷(3-2)=5(间)三人间:9-5=4(间)
4.3角=0.3元 5角=0.5元 假设都是0.3元的 五角的:(31-0.3x80)÷(0.5-0.3)=35(支)

1.假设全是教师栽的 学生:(100x5-200)÷(5-1)=75(人)教师:100-75=25(人)
2.解:设大油瓶x个,小油瓶(55-x)个。
4x+(55-x)/2=80
8x+55-x=160
7x=105
x=15
55-x=40
答:大小油瓶各15、40个.3.解:设完好无损的花瓶为x个,则损坏的花瓶为(250-x)个.
    20x-100(250-x)=4400,
    20x-25000+100x=4400,
      120x-25000=4400,
          120x=4400+25000,
120x=29400,
x=245,则250-x=5.
给分哦!

回答4:

1,鸡有2只,兔子6只
2,孔雀9只,猴子7只
3,3人间要4间,双人间要5间
4,35支

1,教师25,学生75
2,大瓶15,小瓶40

回答5:

1:设鸡有X只,则兔有(8-X)只,又因为鸡有2只脚,兔有4只脚所以有方程式:
2X+(8-X)*4=28求解可得:(答案自己算吧,孩子不能直接给答案要自己算)
剩下的题目都是一个类型的参照第一个的来吧。如果还不明白的话我现场解答!

回答6:

填空:
2 6
9 7
4 5
35
解决问题:

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