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230问答网 > 把Ba(OH)2溶液滴入明矾溶液中.使SO4 2-全部转换为BaSO4沉淀,此时铝元素主要存在形式为什么? Al3+ 么?

把Ba(OH)2溶液滴入明矾溶液中.使SO4 2-全部转换为BaSO4沉淀,此时铝元素主要存在形式为什么? Al3+ 么?

2025-03-24 10:57:55

推荐回答（2个）

回答1：

明矾是KAl(SO4)2,其中Al3+是1mol,SO42-是2mol.沉淀2molSO42-需要2molBa2+,那麼就有4molOH-.而Al3+和4mol的OH-反应是恰好得到AlO2-的,因此主要形式是AlO2-

回答2：

根据反应方程式:Ba(OH)2+KAlSO4=KAlO2+BaSO4↓+H2O,所以铝主要是以偏铝酸根形式存在。

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