已知x⼀2=y⼀3=z⼀4,且x+y+z不等于0,求2x+3y-4z⼀x+y+z的值

2024-12-17 19:08:23
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回答1:

设x/2=y/3=z/4=k
∴x=2k y=3k x=4k
∴(2x+3y-4z)/(x+y+z)
=(4k+9k-16k)/(2k+3k+4k)
=-3k/9k
=-1/3