(log底数4真数3+log底数8真数3)乘(log底数3真数2+log底数9真数2)-log底数二分之一*4次根号下的32=?

2024-12-26 01:51:14
推荐回答(2个)
回答1:

[log(4)3+log(8)3]乘(log(3)2+log(9)2)-log(1/2)*⁴√32
=[1/2*log₂3+1/3*log₂3]×[log₃2+1/2*log₃2]+1/4* log₂32
=5/6*log₂3*3/2*log₃2+1/4*5
=5/6*3/2*(log₂3×log₃2)+5/4
=5/4+5/4
=5/2

回答2:

我写的是14/3