计算1⼀1+2+1⼀1+2+3+...+1⼀1+2+3+...+100

越快越好谢谢大家
2024-12-20 15:59:02
推荐回答(1个)
回答1:

1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
=2/(2x3)+2/(3x4)+……+2/(100x101)
=2x(1/2-1/3+1/3-1/4+……+1/100-1/101)
=2x(1/2-1/101
=1-2/101
=99/101