x(arctanx)的平方的不定积分

2025-01-04 05:25:43
推荐回答(2个)
回答1:

回答2:

分部积分,=1/2∫(arctanX)²dx²=1/2x²(arctanX)²-1/2∫x²/(1+x²)arctanXdx
=1/2x²(arctanX)²-1/2∫(1-1/(x²+1))arctanXdx
后面的会吧