=-16又1/3-5又1/4+2有又2/7+5.25+3又3/7
=-16又1/3+(5.25-5又1/4)+(2有又2/7+3又3/7)
=-16又1/3+5又5/7
=-10又13/21
即a+b=0
cd=1
m≥0
所以原式=1/m+0-|m|
=m-m
=0
(n²-1)/n²
=1-1/n²
=(1-1/n)(1+1/n)
原式=(1-1/3)(1+1/3)(1-1/4)(1+1/4(……(1-1/32)(1+1/32)
=(2/3)(4/3)(3/4)(5/4)……(31/32)(33/32)
约分
=(2/3)(33/32)
=11/16