(1⼀2+1⼀3+...+1⼀2012)(1+1⼀2+1⼀3+...1⼀2011)-(1+1⼀2+...+1⼀2012)(1⼀2+1⼀3+...+1⼀2011)=?

急急急
2025-01-02 12:30:15
推荐回答(1个)
回答1:

设x=1/2+1/3+...+1/2012
y=1/2+1/3+...1/2011
(1/2+1/3+...+1/2012)(1+1/2+1/3+...1/2011)-(1+1/2+...+1/2012)(1/2+1/3+...+1/2011)
=x(1+y)-(1+x)y
=x+xy-y-xy
=x-y
=1/2012