四阶行列式解方程|1 1 2 3| |1 2-x^2 2 3| |2 3 1 5| |2 3 1 9-x^2|求x的值

2025-01-03 20:10:14
推荐回答(2个)
回答1:

1 1 2 3
1 2-x^2 2 3
2 3 1 5
2 3 1 9-x^2

r2-r1,r4-r3
=
1 1 2 3
0 1-x^2 0 0
2 3 1 5
0 0 0 4-x^2

= k(1-x^2)(4-x^2). (k为非零常数)

所以 x=1,-1,2,-2

回答2:

行列式最后结果呢