3x^3y^3(-2⼀3x^2y)^2+(-1⼀3x^2y)^39xy^2

其中x=-1 y=2
2025-01-04 02:31:14
推荐回答(1个)
回答1:

3x^3y^3(-2/3x^2y)^2+(-1/3x^2y)^39xy^2
=3x^3y^3(4x^4y^2/9﹚+﹙-1/27﹚·x^6y^3·9xy^2
=4x^7y^5/3-x^7y^5/3
=x^7y^5
=﹣32