1⼀(1*2)+1⼀(2*3)+1⼀(3*4)+1⼀(4*5)+……+1⼀(99*100)的结果是多少,计算过程怎么算?谢谢。

2024-12-30 06:41:22
推荐回答(2个)
回答1:

1/(1×2)+1/(2×3)+1/(3×4)+1/(4×5)+...+1/(99×100)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/99-1/100
=1-1/100
=99/100

一般的:1/[n(n+1)]=1/n -1/(n+1)

回答2:

1-1/2+1/2+1/3+……+1/99-1/100=99/100