x눀+x-1=0,求多项式x대+2x눀-2的值

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2024-12-22 17:03:23
推荐回答(2个)
回答1:

x²+x-1=0
那么x²+x=1
x³+2x²-2
=x³+x²+x²-2
=x(x²+x)+x²-2
=x+x²-2
=1-2
= -1

回答2:

俊狼猎英团队为您解答

降次法:

X^2=1-X
X^3+2X^2-2
=X(1-X)+2(1-X)-2
=X-X^2+2-2X-2
=-(1-X)-X
=-1