解方程 要过程~~~~~!!! (1)5(1+x)∧2=8.45 (2)x∧2-4x-5=0 (3) (16-2x)(12-2x)=96

(4) (x-1)∧2/x∧2-x-1/x-2=0 急!!!!! 谢谢了!!!
2024-12-14 20:55:13
推荐回答(2个)
回答1:

(1)5(1+x)∧2=8.45
(1+x)²=8.45÷5=1.69=1.3²
1+x=±1.3
x1=0.3 x2=﹣2.3
(2)x²-4x-5=0
x²-4x+4-4-5=0
﹙x-2﹚²=9=3²
x-2=±3
x1=﹣1, x2=5
(3) (16-2x)(12-2x)=96
x²-14x+24=0
﹙x-2﹚﹙x-12﹚=0
x1=2 x2=12
(4) (x-1)∧2/x∧2-x-1/x-2=0
不清晰
(x-1)²/x²-x-1/x-2=0

回答2:

1. (x+1)²=1.69 (x+1)²=1.3² x+1=1.3或x+1=-1.3 x=0.3或x=-2.3
2. (x+1)(x-5)=0 x=-1或x=5
3.(16-2x)(12-2x)=96 192-56x+4x²=96 4x²-56x+96=0 x²-14x+24=0 (x-2)(x-12)=0 x=2或x=12
4. (x-1)²/x²=(x-1)/(x-2) (x-1)/x²=1/(x-2) (x-1)(x-2)=x² x²-3x+2=x² x=2/3