2(x+3)除以五,等于二分之三x减,2(x-7)除以三,方程怎么解?

2025-01-01 09:37:45
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回答1:

2(x+3)除以五,等于二分之三x减,2(x-7)除以三
即2(x+3)/5=3x/2-2(x-7)/3.
两边都乘以30,得12x+36=45x-20x+140,
-104=13x,
x=-8.