求四道初二的整式计算题,十万火急,写出计算过程,答好追加悬赏,谢谢!

2024-12-22 19:24:00
推荐回答(1个)
回答1:

(x+3)(x-5)
=x×x-x×5+3×x-3×5
=x²-5x+3x-15
=x²-2x-15

(x+2)(x+5)
=x×x+x×5+2×x+2×5
=x²+5x+2x+10
=x²+7x+10

(2m+3)(m-4)
=2m×m-2m×4+3×m-3×4
=2m²-8m+3m-12
=2m²-5m-12

(x+1)(x+2)
=x×x+x×2+1×x+1×2
=x²+2x+x+2
=x²+3x+2