解：令y=f(x)=x²-2x+1=(x-1)² x≥1 x-1≥0 (x-1)²≥0 y≥0x-1=√yx=√y +1将x，y互换y=√x+1 (x≥0)所求反函数为f-1(x)=√x+1 (x≥0)
f-1(x)=y^1/2 +1
f-1(x)=√x+1(x>=0)
