解方程(x-1)⼀(x+3)-2=x⼀(3-x) 要求过程与解释...

2024-12-17 05:59:31
推荐回答(5个)
回答1:

(x+3)(x-3)是最简公分母,方程两边同时乘以最简公分母可以使分式方程变成正式方程,从而运算,
记得做完要验根,分母不能为负数。
过程:方程两边同时乘以(x+3)(x-3)得:(x-1)(x-3)-2(x+3)(x-3)=-x(x+3)
x^2-4x+3-2x^2+18=-x^2-3x
-4x+21 =-3x
x=21
验证:x=21是原方程的解

回答2:

先通分(x-1)/(x+3)-2(x+3)/(x+3)=x/(x-3)
(-x-7)/(x+3)=x/(x-3)要想把等式两边的分母都消去的话就得乘以两边分母的最小公倍数即最简公分母(x-3)·(x+3)那么就有(-x-7)(3-x)=x(x+3)去括号得x=21
再将x=21代入原分式方程(分式方程必须将解出来的根代入原式,这是为了检验是不是增跟)满足方程,所以它的解x=21

回答3:

分式方程首先要先去分母,这么做是为了化掉分母
还有谁说两边乘以(x-3)?你就照这思路做就行了,之后简单的,过程自己动笔写下

回答4:

(x-3)是等号右边3-X的加负号。。。。

回答5:

(x-3)是因为 给等号右边的分式提取一个负号出来
就会由X/(3-X)变成 -X/(X-3)
只有两边同时乘以最简公分母 才可以化成等式方程

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