4x²+2(p-2)x-2p²-p+1>0
4x²+(2p-4)x-(2p-1)(p+1)>0
(2x+2p-1)(2x-p-1)>0
(比较(1-2p)/2与(1+p)/2的大小,谈论p)
p<0时,1-2p>1+p,A={ x | x<(1+p)/2 或 x>(1-2p)/2 }
p=0时,1-2p=1+p,A={ x | x ≠ 1/2 }
p>0时,1-2p<1+p,A={ x | x<(1-2p)/2 或 x<(1+p)/2 }
因为A∩[-1,1]≠空集,所以(画数轴看)
p<0时,(1+p)/2≥-1 且(1-2p)/2≤1,解得-1/2≤p<0
p=0时,A∩[-1,1]=[-1,1/2)∪(1/2,1]≠空集,解得p=0
p>0时,(1-2p)/2≥-1 且(1+p)/2≤1,解得0
综上所诉,p的取值范围是[ -1/2 , 1 ]