解:用平方差公式啊
=(1-1/2)(1+1/2)(1-1/3)(1+1/3)……(1-1/100)(1+1/100)
=(1/2)(3/2)(2/3)(4/3)……(99/100)(101/100)
=(1/2)(101/100)
=101/200
原式=(1-1/2)(1+1/2)(1-1/3)(1+1/3)...*(1-1/100)(1+1/100)
=1/2*3/2*2/3*4/3...*99/100*101/100
=1/2*101/100
=101/200
初二做过，忘了...........
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