先化简,再求值:(a+2⼀a*a-4)+(1⼀a+2),其中a=3

2024-12-26 16:28:22
推荐回答(3个)
回答1:

(a+2/a*a-4)+(1/a+2)

=(a+2)/(a-2)(a+2)+1/(a+2)
=1/(a-2)+1/(a+2)
=2a/(a-2)(a+2)
=6/(3-2)(3+2)
=6/5

回答2:

=a+2/(a+2)(a-2)+1/a+2
=1/a-2+1/a+2
通分=2a/a*a-4
a=3代入
=2*3/3*3-4
=6/5

回答3:

括号没有用好,表达不严密。搞不懂。