System.Windows.Forms.DialogResult dr;
dr = openfiledialog1.ShowDialog();
if (dr == System.Windows.Forms.DialogResult.OK)
{
richTextBox1.LoadFile(openfiledialog1.FileName, System.Windows.Forms.RichTextBoxStreamType.PlainText);
}
用这个,已经调试成功,使用openfiledialog1打开txt文件
System.Windows.Forms.DialogResult dr;
dr = openfiledialog1.ShowDialog();
if (dr == System.Windows.Forms.DialogResult.OK)
{
richTextBox1.LoadFile(openfiledialog1.FileName, System.Windows.Forms.RichTextBoxStreamType.PlainText);
}