在java中怎么比较三个整数大小例如(a , b, c);并从小到大输出

2025-03-23 19:05:12
推荐回答(5个)
回答1:

用冒泡排序,对三个数字按照由小到大进行排序。以23、11、17为例,代码如下:

import java.util.Scanner;

public class woo {

static int[] bubbleSort(int[] date) {

boolean isSwap;

for(int j = 1; j < date.length; j++) {

isSwap = false;

for(int i = 0; i < date.length - j; i++) {

if(date[i] > date[i+1]) {

date[i] = date[i] ^ date[i+1];

date[i+1] = date[i] ^ date[i+1];

date[i] = date[i] ^ date[i+1];

isSwap = true;

}

}

if(isSwap == false) 

break;

}

return date;

}

public static void main(String args[]) {

int date[] = new int[3];

System.out.println("输入三个整数:");

Scanner num = new Scanner(System.in);

for(int i = 0;i < date.length; i++)

date[i] = num.nextInt();

date = bubbleSort(date);

for(int count = 0; count < date.length; count++) 

System.out.print(date[count] +"\t");

System.out.println("");

}

}

扩展资料

通常排序算法,可以分为两大类。

非线性时间比较类排序:通过比较来决定元素间的相对次序,由于其时间复杂度不能突破O(nlogn),因此称为非线性时间比较类排序。包括交换排序、插入排序、选择排序、归并排序。

线性时间非比较类排序:不通过比较来决定元素间的相对次序,它可以突破基于比较排序的时间下界,以线性时间运行,因此称为线性时间非比较类排序。包括计数排序、桶排序、计数排序。

参考资料:冒泡法排序——百度百科

回答2:

package work;

import java.util.Scanner;//导包,获取键盘输入

/**

* 键盘输入A、B、C三个值,按从大到小顺序输出。

**/

public class Demo01 {

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

System.out.println("输入数字a");

int a = sc.nextInt();

System.out.println("输入数字b");

int b = sc.nextInt();

System.out.println("输入数字c");

int c = sc.nextInt();

if (c < a && c < b && b < a) {// 通过比较c

System.out.println("一号a:" + a+"\n二号b:" + b+"\n三号c:" + c);

} else if (c < a && b < c && b < a) {

System.out.println("一号a:" + a+"\n二号c:" + c+"\n三号b:" + b);

} else if (c < a && c < b && a < b) {

System.out.println("一号b:" + b+"\n二号a:" + a+"\n三号c:" + c);

} else if (a < c && a < b && c < b) {

System.out.println("一号b:" + b+"\n二号c:" + c+"\n三号a:" + a);

} else if (a < b && a < c && b < c) {

System.out.println("一号c:" + c+"\n二号b:" + b+"\n三号a:" + a);

} else if (b < a && b < c && a < c) {

System.out.println("一号c:" + c+"\n二号a:" + a+"\n三号b:" + b);

}

}

}

解题思路:

可以用if else if语句判断,通过else if多次判断来输出。

假设C

if (c < a && c < b && b < a){

System.out.println("老大" + a,"老二"+b+"老三"+c);

} else if(比较条件){ }

按这个思路一一判断过去,得出A B C 三个值的大小。

扩展资料

java中三个整数排列的其他解法

import java.util.Scanner;

public class lianxi34 {

public static void main(String[] args) {

Scanner s = new Scanner(System.in);

System.out.println("输入3个整数:");

int a = s.nextInt();

int b = s.nextInt();

int c = s.nextInt();

if(a < b) {

int  t = a;

a = b;

b = t;

}

if(a < c) {

int t = a;

a = c; 

c = t;

}  

if(b < c) { 

int t = b; 

b = c;  

c = t; 

System.out.println("从大到小的顺序输出:");

System.out.println(a + " " + b + " " + c);}}

回答3:

import java.util.*;
public class Exercise06
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in); //利用键盘输入功能
System.out.print("a=");
int a = input.nextInt() ; //输入数字a 只能为int类型
System.out.print("b=");
int b = input.nextInt() ;
System.out.print("c=");
int c = input.nextInt() ;
Exercise06 e = new Exercise06() ;
e.sort(a,b,c);
}
void sort(int a,int b,int c)
{
int temp = 0 ;
if(a>b){
temp = a;
a = b ;
b = temp ;
}
if(a>c){
temp = a;
a = c ;
c = temp ;
}
if(b>c){
temp = b;
b = c ;
c = temp ;
}
System.out.println(a+","+b+","+c);
}
}

不过我还是建议你多用一楼的方法

回答4:

class Test4
{
public static void main(String[] args)
{
int[] arr={1,4,2};//定义数组。
Sort s=new Sort();
s.sort(arr);
s.print(arr);
}
}
class Sort//定义方法排序数组。
{
void sort(int[] a)
{
for (int i=0;i {
for (int j=i+1;j {
if (a[i]>a[j])
{
int temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
}
//定义方法打印。
void print(int[] a)
{
System.out.print("[");
for (int i=0;i {
if (i {
System.out.print(a[i]+",");
}else
System.out.print(a[i]+"]");
}
}
}

//该方法比较灵点,希望对你有助。

回答5:

if(aif(bSystem.out.println("a}else if(cSystem.out.println("c}else{
System.out.println("a}
}else if(a>b){
if(b>c){
System.out.println("a>b>c");
}else if(c>a){
System.out.println("c>a>b");
}else{
System.out.println("a>c>b");
}
}

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