C++语言编写一万年历系统!高分!

2025-03-06 05:02:50
推荐回答(2个)
回答1:

实现C++的万年历类
一直想做这个东西,从vc知识库搜索到一个,可是代码算法有问题,许多的结果都是错的。其他的代码都是js的,没办法,自己动手。代码虽短,心意一片。

从此后你想为自己的软件增添点特色,放心的用吧,可以任意修改,传播。

#ifndef _CALENDAR_H
#define _CALENDAR_H

#include

struct myDATE{
int year;
int month;
int day;
bool isRunYue;
};

class calendar{
public:
calendar(){};
~calendar(){};

LONG lDaysFrom1900(myDATE date);//date与1900年相差的天数
UINT lYearDays(UINT y);//农历y年的总天数
UINT leapDays(UINT y);//传回农历 y年闰月的天数
UINT leapMonth(UINT y);// 传回农历 y年闰哪个月 1-12 , 没闰传回 0
UINT monthDays(UINT y,UINT m);//传回农历 y年m月的总天数
myDATE Lunar(myDATE date);//输入阳历日期,返回阴历日期
char* dayOfWeek(myDATE date);//输入阳历日期,返回星期几
char* getLunarString (myDATE date );// 输入阴历日期,得到表示农历的字串
UINT solarDays(UINT y,UINT m);//传回国历 y年某m+1月的天数

private:
char m_slunar[100];//用于存储农历信息

static DWORD lunarInfo[];//
static UINT solarMonth[];
static char sSolarTerm[];
static DWORD dTermInfo[];
static char sFtv[];

};
#endif

#include "calendar.h"
#include

DWORD calendar::lunarInfo[]={
0x04bd8,0x04ae0,0x0a570,0x054d5,0x0d260,0x0d950,0x16554,0x056a0,0x09ad0,0x055d2,
0x04ae0,0x0a5b6,0x0a4d0,0x0d250,0x1d255,0x0b540,0x0d6a0,0x0ada2,0x095b0,0x14977,
0x04970,0x0a4b0,0x0b4b5,0x06a50,0x06d40,0x1ab54,0x02b60,0x09570,0x052f2,0x04970,
0x06566,0x0d4a0,0x0ea50,0x06e95,0x05ad0,0x02b60,0x186e3,0x092e0,0x1c8d7,0x0c950,
0x0d4a0,0x1d8a6,0x0b550,0x056a0,0x1a5b4,0x025d0,0x092d0,0x0d2b2,0x0a950,0x0b557,
0x06ca0,0x0b550,0x15355,0x04da0,0x0a5d0,0x14573,0x052d0,0x0a9a8,0x0e950,0x06aa0,
0x0aea6,0x0ab50,0x04b60,0x0aae4,0x0a570,0x05260,0x0f263,0x0d950,0x05b57,0x056a0,
0x096d0,0x04dd5,0x04ad0,0x0a4d0,0x0d4d4,0x0d250,0x0d558,0x0b540,0x0b5a0,0x195a6,
0x095b0,0x049b0,0x0a974,0x0a4b0,0x0b27a,0x06a50,0x06d40,0x0af46,0x0ab60,0x09570,
0x04af5,0x04970,0x064b0,0x074a3,0x0ea50,0x06b58,0x055c0,0x0ab60,0x096d5,0x092e0,
0x0c960,0x0d954,0x0d4a0,0x0da50,0x07552,0x056a0,0x0abb7,0x025d0,0x092d0,0x0cab5,
0x0a950,0x0b4a0,0x0baa4,0x0ad50,0x055d9,0x04ba0,0x0a5b0,0x15176,0x052b0,0x0a930,
0x07954,0x06aa0,0x0ad50,0x05b52,0x04b60,0x0a6e6,0x0a4e0,0x0d260,0x0ea65,0x0d530,
0x05aa0,0x076a3,0x096d0,0x04bd7,0x04ad0,0x0a4d0,0x1d0b6,0x0d250,0x0d520,0x0dd45,
0x0b5a0,0x056d0,0x055b2,0x049b0,0x0a577,0x0a4b0,0x0aa50,0x1b255,0x06d20,0x0ada0
};
UINT calendar::solarMonth[]={31,28,31,30,31,30,31,31,30,31,30,31};
UINT calendar::lYearDays(UINT y)
{
UINT i, sum = 348;
for(i=0x8000; i>0x8; i>>=1)
{
sum += (lunarInfo[y-1900] & i)? 1: 0;
}
return(sum+leapDays(y));
}

UINT calendar::leapDays(UINT y)
{
if(leapMonth(y))
{
return (lunarInfo[y-1900] & 0x10000)? 30: 29;
}
else
{
return 0;
}
}

UINT calendar::leapMonth(UINT y)
{
return lunarInfo[y-1900] & 0xf;
}

UINT calendar::monthDays(UINT y,UINT m)
{
return (lunarInfo[y-1900] & (0x10000>>m))? 30: 29;
}
LONG calendar::lDaysFrom1900(myDATE date)
{
LONG days;

days=365*date.year+(date.year-1)/4-(date.year-1)/100+(date.year-1)/400-
(365*1900+(1900-1)/4-(1900-1)/100+(1900-1)/400);

for(int i=0;i {
days+=solarMonth[i];
}
days+=date.day;
if((date.year%4==0&&date.year%100!=0)||date.year%400==0)
{
if(date.month>2)
{
days++;
}
}
return days;
}

myDATE calendar::Lunar(myDATE date)
{
LONG offset;
int i, leap=0, temp=0;
myDATE retdate;

offset=lDaysFrom1900(date)-30;

for(i=1900; i<2050 && offset>0; i++)
{
temp = lYearDays(i);
offset -= temp;
}

if(offset<0)
{
offset += temp;
i--;
}

retdate.year = i;

leap = leapMonth(i);
bool isLeap = false;

for(i=1; i<13 && offset>0; i++)
{
if(leap>0 && i==(leap+1) && isLeap==false)
{
--i;
isLeap = true;
temp = leapDays(retdate.year);
}
else
{
temp = monthDays(retdate.year, i);
}
if(isLeap==true && i==(leap+1))
{
isLeap = false;
}
offset -= temp;
}
if(offset==0 && leap>0 && i==leap+1)
{
if(isLeap)
{
isLeap = false;
}
else
{
isLeap = true;
--i;
}
}
if(offset<=0)
{
offset += temp;
--i;
}
retdate.month = i;
retdate.day = offset ;
retdate.isRunYue=isLeap;
return retdate;
}

char* calendar::getLunarString (myDATE date)
{
TCHAR szNongli[30], szNongliDay[10],szShuXiang[10];
const char *cTianGan[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; /*天干名称*/
const char *cDiZhi[] = {"子","丑","寅","卯","辰","巳","午", "未","申","酉","戌","亥"}; /*地支名称*/
const char *cShuXiang[] = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"}; /*属相名称*/
const char *cDayName[] = { "*","初一","初二","初三","初四","初五", /*农历日期名*/
"初六","初七","初八","初九","初十",
"十一","十二","十三","十四","十五",
"十六","十七","十八","十九","二十",
"廿一","廿二","廿三","廿四","廿五",
"廿六","廿七","廿八","廿九","三十"};
const char *cMonName[] = {"*","正","二","三","四","五","六", "七","八","九","十","十一","腊"};

/*--生成农历天干、地支、属相 ==> wNongli--*/
int nShuXiang = ((date.year - 4) % 60) % 12;
if ( nShuXiang < 0 || nShuXiang >= sizeof(cShuXiang)/sizeof(cShuXiang[0]) )
{
return NULL ;
}
wsprintf(szShuXiang,"%s",cShuXiang[nShuXiang]);
int nTianGan = ((date.year - 4) % 60) % 10;
if ( nTianGan < 0 || nTianGan >= sizeof(cTianGan)/sizeof(cTianGan[0]) )
{
return NULL;
}
int nDiZhi = ((date.year - 4) % 60) % 12;
if ( nDiZhi < 0 || nDiZhi >= sizeof(cDiZhi)/sizeof(cDiZhi[0]) )
{
return NULL;
}

wsprintf(szNongli,"%s(%s%s)年",szShuXiang,cTianGan[nTianGan],cDiZhi[nDiZhi]);

/*--生成农历月、日 ==> wNongliDay--*/
if ( date.month < 0 || date.month >= sizeof(cMonName)/sizeof(cMonName[0]) )
{
return NULL;
}

if (date.isRunYue)
{
wsprintf(szNongliDay,"闰%s",cMonName[date.month]);
}
else
{
strcpy(szNongliDay,cMonName[date.month]);
}

strcat(szNongliDay,"月");
if ( date.day < 0 || date.day >= sizeof(cDayName)/sizeof(cDayName[0]) )
{
return NULL;
}

strcat(szNongliDay,cDayName[date.day]);
strcat(szNongli,szNongliDay);
sprintf(m_slunar,szNongli);
return m_slunar;
}
char* calendar::dayOfWeek(myDATE date)
{
char *cWeekName[] = {"星期日","星期一","星期二","星期三","星期四","星期五","星期六"};

if(date.month==1||date.month==2)
{
date.month+=12;
date.year--;
}
return cWeekName[(date.day+1+2*date.month+3*(date.month+1)/5+date.year+date.year/4-date.year/100+date.year/400)%7];
}

UINT calendar::solarDays(UINT y,UINT m)
{
if(m==1)//2月
{
return(((y%4 == 0) && (y%100 != 0) || (y%400 == 0))? 29: 28);
}
else
{
return(solarMonth[m]);
}
}

回答2:

考虑了历史上丢失的十几天没,好像没有考虑,看来也是错的。在大概十三四世纪的时候,西方因为原来的历法不合理,和天文观测相差了十几天,通过修改日期把那十几天跳过去了,而农历没有经历过,因此需要考虑这个问题。除此之外,还应该研究之前西方用的什么历法,肯定不是现在这样的。

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