若x눀-3x+1=0,求(1)x눀+1⼀x눀 (2)x-1⼀x的值。

2024-12-28 05:21:56
推荐回答(2个)
回答1:

x²-3x+1=0
同除以x得
x-3+1/x=0
x+1/x=3
(x+1/x)²=9
x²+1/x²+2=9
x²+1/x²=7

因为x²+1/x²=7
(x²-2+1/x²)+2=7
(x-1/x)²=5
x-1/x=±√5

回答2:

1)
x²-3x+1=0
x²=3x-1
x²+1/x² =3x-1+1/(3x-1)
=(9x²-6x+2)/(3x-1)
=(9(3x-1)-6x+2))/(3x-1)
=(21x-7)/(3x-1)
=7

2)x-1/x=(x²-1)/x=(3x-1-1)/x
=(3x-2)/x
=3-2/x
x²-3x+1=0
x=(3±√5)/2
3-2/x=±√5