#include
intmonthsize(intyear,intmonth){
intdays;
if(month==2){
if(year%4==0&&year%100!=0||year%400==0)
return29;
return28;
}
switch(month){
case1:
case3:
case5:
case7:
case8:
case10:
case12:days=31;break;
case4:
case6:
case9:
case11:days=30;break;
}
returndays;
}
intmain(){
intyear,month,day,days;
printf("年月日:");
while(scanf("%d%d%d",&year,&month,&day)==3){
days=monthsize(year,month);
if(days==day){
if(month==12){
++year;
month=1;
day=1;
}
else++month;
}
else++day;
printf("第二天是:%d/%02d/%02d\n",year,month,day);
printf("年月日(qtoquit):");
}
return0;
}
扩展资料
输入两个任意日期计算相隔天数
#include
#include
#include
#include
#include
intget_days（constchar*from，constchar*to）;
time_tconvert（intyear，intmonth，intday）;
intmain（）
{
constchar*from=“2013-3-15”;
constchar*to=“2015-8-14”;
intdays=get_days（from，to）;
printf（“From：％s\nTo：％s\n”，from，to）;
printf（“％d\n”，天）；
个系统（“暂停”）；
返回0;
}
20time_tconvert（intyear，intmonth，intday）
{
tminfo={0};
info.tm_year=year-1900;
info.tm_mday=天;
返回mktime（＆info）;
}
intget_days（constchar*from，constchar*to）
{
int年，月，日；
sscanf（from，“％d-％d-％d”，＆year，＆month，＆day）;
intfromSecond=（int）convert（年，月，日）;
sscanf（to，“％d-％d-％d”，＆year，＆month，＆day）;
inttoSecond=（int）convert（年，月，日）;
return（toSecond-fromSecond）/24/3600;
}
源程序如下：
#include "pch.h"
#define _CRT_SECURE_NO_WARNINGS
#include
using namespace std;
int main()
{
int s[2][13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31,
0,31,29,31,30,31,30,31,31,30,31,30,31, };
int year = 0;
int month = 0;
int day = 0;
int n, i, daytemp;
int flag = 0;
int nyear = 0, nmonth = 0, nday = 0;
printf("输入年月日\n");
scanf("%d%d%d", &year, &month, &day);
//printf("输入天数\n");
//scanf("%d",&n);
n = 1;
if (year < 0 || month < 0 || month>12 || day < 1 || n < 0)
{
printf("输入数据错误\n");
return 1;
}
daytemp = day + n;//累加天数
if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)//闰年置1
flag = 1;
if (day > s[flag][month])
{
printf("输入日期与年月不符.\n");
return 1;
}
if (daytemp <= s[flag][month])//当前日期加天数在本月
{
nyear = year;
nmonth = month;
nday = daytemp;
}
else
{
i = month;
nyear = year；
while (daytemp > s[flag][i])//循环递减，直到当前日期加天数在本月
{
daytemp = daytemp - s[flag][i];
i++;
if (i > 12)//超过一年，年累加
{
nyear++;
if ((nyear % 4 == 0 && nyear % 100 != 0) || nyear % 400 == 0)
flag = 1;
else
flag = 0;
i = i - 12;
}
}
nmonth = i;
nday = daytemp;
}
printf("%d年%d月%d日第%d天后是:\n", year, month, day, n);
printf("%d年%d月%d日\n", nyear, nmonth, nday);
return 0;
}
程序运行结果如下：
扩展资料：
其他实现方式：
int monthsize(int year, int month) {
int days;
if (month == 2) {
if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
return 29;
return 28;
}
switch (month) {
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:days = 31; break;
case 4:
case 6:
case 9:
case 11: days = 30; break;
}
return days;
}
int main()
int year, month, day, days;
printf("年 月 日:");
while (scanf("%d%d%d", &year, &month, &day) == 3) {
days = monthsize(year, month);
if (days == day) {
if (month == 12) {
++year;
month = 1;
day = 1;
}
else ++month;
}
else ++day;
printf("第二天是:%d/%02d/%02d\n", year, month, day);
printf("年 月 日(q to quit):");
}
return 0;
}
#include
int main()
{
int a,b,c;
scanf("%d %d %d",&a,&b,&c);//输入年月日
printf("%d %d %d",a,b,c++);//输出
return 0；
}
如上代码，满意请采纳
#include
int main()
{
int s[2][13]={0,31,28,31,30,31,30,31,31,30,31,30,31,
0,31,29,31,30,31,30,31,31,30,31,30,31,};
int year=0;
int month=0;
int day=0;
int n,i,daytemp;
int flag=0;
int nyear=0,nmonth=0,nday=0;
printf("输入年月日\n");
scanf("%d%d%d",&year,&month,&day);
//printf("输入天数\n");
//scanf("%d",&n);
n=1;
if(year<0||month<0||month>12||day<1||n<0)
{
printf("输入数据错误\n");
return 1;
}
daytemp=day+n;//累加天数
if((year%4==0&&year%100!=0)||year%400==0)//闰年置1
flag=1;
if(day>s[flag][month])
{
printf("输入日期与年月不符.\n");
return 1;
}
if(daytemp<=s[flag][month])//当前日期加天数在本月
{
nyear=year;
nmonth=month;
nday=daytemp;
}
else
{
i=month;
nyear=year;
while(daytemp>s[flag][i])//循环递减，直到当前日期加天数在本月
{
daytemp=daytemp-s[flag][i];
i++;
if(i>12)//超过一年，年累加
{
nyear++;
if((nyear%4==0&&nyear%100!=0)||nyear%400==0)
flag=1;
else
flag=0;
i=i-12;
}
}
nmonth=i;
nday=daytemp;
}
printf("%d年%d月%d日第%d天后是:\n",year,month,day,n);
printf("%d年%d月%d日\n",nyear,nmonth,nday);
return 0;
}
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