用因式分解法解下列方程:

2024-12-14 01:45:20
推荐回答(2个)
回答1:

1.(3x-1)(x-1)=0
2.(3-x)(x+1)=0
3.(3x-1)²=0
4.(x-3)(x+2)=0
5.(5x-3)(x-3)=0
^_^希望能够帮助到你

回答2:

(1)(2x-1)²-x²=0
(2x-1+x)(2x-1-x)=0
(3x-1)(x-1)=0
x1=1/3 x2=1

(2)x(x+1)=3(x+1)
(x-3)(x+1)=0
x1=3 x2=-1

(3)9x²-6x+1=0
(3x-1)²=0
x=1/3

(4)(x-1)(x+2)=2(x+2)
(x-1-2)(x+2)=0
(x-3)(x+2)=0
x1=3 x=-2

(5)(x-3)²+4x(x-3)=0
(x-3+4x)(x-3)=0
(5x-3)(x-3)=0
x1=3/5 x2=3