在“探究固体熔化时温度的变化规律”的实验中,两个实验小组分别设计如图的甲、乙所示的实验装置进行实验

2025-04-02 18:35:25
推荐回答(1个)
回答1:

(1)甲方案直接把试管放在酒精灯上加热,试管内的固体受热不均.乙方案把试管放在水中加热,试管内的固体受热均匀,探究固体熔化的效果比较科学.
(2)在时间和温度图象上描绘(0,63)(2,68)(4,73)(6,77)(8,80)(10,80)(12,80)(14,80)(16,83)(18,87)(20,92)各点,然后用光滑的曲线连接起来.如图.

(3)由时间和温度的图象知,当固体升高到80℃时,吸收热量,温度保持80℃不变,该固体熔化时有一定的熔化温度,所以该固体是晶体.
(4)当固体升高到80℃时,吸收热量,温度保持80℃不变,所以该晶体的熔点是80℃.
晶体在第10min时,晶体正在熔化,所以此时晶体处于固液共存状态.晶体从第8min开始熔化到第14min熔化结束,晶体熔化经过了6min.
(5)此固体是晶体,所以此类固体的熔化规律是不断吸收热量,温度保持不变.
(6)当烧杯中的冰块有大半熔化时,烧杯中的冰处于熔化状态,温度是熔点,试管中的冰,最高温度达到熔点,但是不能从烧杯中吸收热量,不能熔化.
故答案为:(1)乙;探究固体熔化时,采用水浴法,固体受热均匀;(2)如上图;(3)固体熔化时,有一定的熔化温度;(4)80;固液共存;6;(5)不断吸收热量,温度保持不变;(6)C.

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