已知一个电水壶额定电压为220v额定功率为1500w若实际电压只有110v则电水壶的实际功率是多少?

2025-03-30 18:08:18
推荐回答(4个)
回答1:

1、额定电压为220V,功率为1500W,则电水壶发热管的电阻为:R=220*220/1500=32.26欧姆
2、改变电压,电水壶的电阻是不变的,则功率为:P=110*110/32.6=275W
改变电压后,电水壶的功率为375W。

回答2:

电压是额定电压的一半,那么功率就是额定功率的四分之一。根据p=u*u/r

回答3:

R=UU/P=220*220/1500

P1=U1U1/R=110*110/(220*220/1500)=375w

回答4:

由P=UI得
I=P/U=75/11

当u=110时
P=75/11×110=750w

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