已知:x+y=5,xy=-2,求(1)x除y+y除x(2)x的平方+xy+y的平方

2024-12-26 01:19:38
推荐回答(5个)
回答1:

1. x/y+y/x=(x²+y²)/xy
=[(x+y)²-2xy]/xy
=[5²-2×(-2)]/(-2)
=-14.5
2. x²+xy+y²
=(x+y)²-xy
=5²+2
=27

回答2:

都快初二的人了,为什么到现在连这种题都不会做

回答3:

x÷y+y÷x
=(x²+y²)/(xy)
=【(x+y)²-2xy】/(xy)
=(25+4)/(-2)
= -29/2

x²+xy+y²
=(x+y)²-xy
=25+2
=27

回答4:

(x/y)+(y/x)=(x^2+y^2)/(x*y)=((x+y)^2-2x*y)/(xy)

回答5:

(1)x/y+y/x=(x2+y2)/xy=[(x+y)2-2xy]/xy=(25+4)/-2=-29/2
(2) x2+xy+y2=(x+y)2-xy=25+2=27