解答:由根的判别式Δ=m²-4﹙m+1﹚=0∴解得:m=2±2√2
x^2+m/(m+1) x+1/(m+1)=[x+m/2(m+1)]^2+1/(m+1)-[m/2(m+1)]^2所以1/(m+1)-[m/2(m+1)]^2=0m=1+根号3或-根号3
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