已知函数f(x)={x+2,x≤0① -x+2,x>0②,则不等式f(x)≥x눀的解集?

2024-12-16 01:21:16
推荐回答(1个)
回答1:

1、当x≤0时,f(x)≥x²,(x+2)^2>=x^2,4x+4>=0,x>=-1
此时,-1<=x<=0
2、当x>0时,f(x)≥x²,(-x+2)^2>=x^2,4x<=4,x<=1
此时,0综上,-1<=x<=1