x²+2x+y²-6y+10=0x²+2x+1+y²-6y+9=0(x+1)²+(y-3)²=0得x+1=0 x=-1y-3=0 y=3
x的平方+2x+y的平方-6y+10=0(x+1)^2+(y-3)^2=0x+1=0 y-3=0x=-1 y=3
x^2+2x+y^2-6y+10=(x+1)^2+(y-3)^2=0所以x+1=y-3=0所以x=-1,y=3
x=-1,y=3
