已知x^2=1⼀2求(x+1⼀2)(x-1⼀2)(x^4-1⼀2x^2+1⼀16)的值

2024-12-11 20:53:44
推荐回答(2个)
回答1:

原式=(x²-1/4)[(x²)²-1/2x²+1/16)
=(1/2-1/4)(1/4-1/2×1/2+1/16)
=1/2×1/16
=1/32

回答2:

(x+1/2)(x-1/2)(x^4-1/2x^2+1/16)=(x^2-1/4)(x^2(x^2-1/2)+1/16)
将x^2=1/2带入上式
=1/4(1/2(1/2-1/2)+1/16)
=1/64