已知x눀-4x+y눀-10y+29=0,求x눀y눀+2x대y눀+x四次方y눀的值

2024-12-20 13:05:46
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回答1:

x²-4x+y²-10y+29=0
(x²-4x+4)+(y²-10y+25)=0
(x-2)²+(y-5)²=0
x-2=0,y-5=0
x=2,y=5
x²y²+2x³y²+x四次方y²
=x²y²(1+2x+x²)
=x²y²(x+1)²
=4×25×9
=900