用循环语句编写程序,其功能是计算: s=1+12+123+1234+12345+123456+1234567

2025-02-11 14:32:22
推荐回答(5个)
回答1:

void main()
{
int i;
double b=2,s=1,t=1;
for(i=1;i<8;i++)
{printf("%f\n",t);
t=t*10+b;

s=s+t; b++;

}

printf("%f\n",s);
system("pause");
}
关键是会不会溢出

回答2:

我就知写循环体部分了
int s=0,t=1,j=2,i;
for(i=0;i<7;i++)
{
s+=t;
t=t*10+j;
j++;
}

回答3:

sum=0;
i=1;
j=1;
b;
while(1)
{sum+=i
i=i*10+j++;
if(j==8) break;
}

回答4:

#include
int main()
{
int i,j=0,k=1;
for(i=0;i<7;i++)
{

j=i*k+j;
k*=10;

}
printf("%d\n",j);
}

回答5:

#include "stdio.h"
void main()
{
int sum=0;
int j=1,i=1;
while(1)
{
sum+=i;
i=i*10+(++j);
if(j==8) break;
}
printf("s=1+12+123+1234+12345+123456+1234567=%d",sum);
}

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