过椭圆其中一个焦点作垂直于x轴的直线的长度公式是什么?

是b除以a吗。。还是什么??在线等!!麻烦速度!!!!!
2025-04-02 23:40:19
推荐回答(3个)
回答1:

解:设椭圆方程为x²/a²+y²/b²=1,用x=c或x=-c代入得:

y²=b²(1-c²/a²)=b²(a²-c²)/a²=b⁴/a²,故y=±b²/a

设弦AB的端点A(±c,-b²/a),B(±c,b²/a);于是得:

︱AB︱=b²/a-(-b²/a)=2b²/a

p=︱AB/2︱=a(1-e²)=a(1-c²/a²)=a(a²-c²)/a²=b²/a叫做椭圆的“焦点参数”,2p=︱AB︱=2b²/a就是所谓的“焦点弦”之长。

扩展资料

椭圆上任意一点到F1,F2距离的和为2a,F1,F2之间的距离为2c。而公式中的b²=a²-c²。b是为了书写方便设定的参数。

又及:如果中心在原点,但焦点的位置不明确在X轴或Y轴时,方程可设为mx²+ny²=1(m>0,n>0,m≠n)。即标准方程的统一形式。

椭圆的面积是πab。椭圆可以看作圆在某方向上的拉伸,它的参数方程是:x=acosθ , y=bsinθ。

回答2:

过椭圆其中一个焦点作垂直于x轴的弦的长度公式是什么?
解:设椭圆方程为x²/a²+y²/b²=1,用x=c或x=-c代入得:
y²=b²(1-c²/a²)=b²(a²-c²)/a²=b⁴/a²,故y=±b²/a
设弦AB的端点A(±c,-b²/a),B(±c,b²/a);于是得:
︱AB︱=b²/a-(-b²/a)=2b²/a
p=︱AB/2︱=a(1-e²)=a(1-c²/a²)=a(a²-c²)/a²=b²/a叫做椭圆的“焦点参数”,2p=︱AB︱=2b²/a
就是所谓的“焦点弦”之长。
不知道你的“ 过椭圆其中一个焦点作垂直于x轴的直线的长度”是指弦AB?还是焦参数P?
故把两个结果都写出来了,供你选择。

回答3:

直线过焦点(c,0)或(-c,0)。垂直于x轴交椭圆于m、n(±c,±y)
把m或n的坐标带入椭圆方程得
c^2/a^2+y^2/b^2=1
化简得mn=2y=2b乘根号下(1-c^2/a^2)

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