error C2143: syntax error : missing ✀;✀ before ✀type✀ 求解啊 （附源程序）

3个错误

jiami (int x)
这个函数最后少了两个}

scanf_s("%d",&choice);
改为
scanf("%d",&choice);

改好的：
#include
#include

char *str=NULL;
char c;
int i = 0;
int choice;
char ch;

jiami (int x)
{
switch(x)
{
case 1:

if((c>='a'&&c<='z') || (c>='A'&&c<='Z'))
{
c=c+3;
if((c>'Z'&&c<='Z'+3 )||( c>'z'))
c=c-26;
return c;
}

break;

case 2:

if((c>='a'&&c<='z') || (c>='A'&&c<='Z'))
{
c=c-3;
if((c<'A')||( c<'a' && c>='a'-3))
c=c+26;
return c;
}
break;

}
}
int main()
{

while(1)

{
printf("\n1.加密 2.解密 3.退出\n");
// scanf_s("%d",&choice);
scanf("%d",&choice);

str = (char *)malloc(1);
printf("请输入密文字符串:");
while((c=getchar())!='\n')
{
jiami (choice);

str[i++] = c;
}
str[i] = 0;
printf("明文字符串为：%s\n",str);
}

}

#include
#include

char *str=NULL;
char c;
int i = 0;
int choice;
char ch;

int jiami (int x)//要有返回值
{

switch(x)
{
case 1:

if((c>='a'&&c<='z') || (c>='A'&&c<='Z'))
{
c=c+3;
if((c>'Z'&&c<='Z'+3 )||( c>'z'))
c=c-26;
return c;
}

break;

case 2:

if((c>='a'&&c<='z') || (c>='A'&&c<='Z'))
{
c=c-3;
if((c<'A')||( c<'a' && c>='a'-3))
c=c+26;
return c;
}
break;
}//少右括号

}//少右括号
int main()
{

while(1)

{
printf("\n1.加密 2.解密 3.退出\n");
scanf_s("%d",&choice);

str = (char *)malloc(1);
printf("请输入密文字符串:");
while((c=getchar())!='\n')
{
jiami (choice);

str[i++] = c;
}
str[i] = 0;
printf("明文字符串为：%s\n",str);
}

return 0;//返回值
}