x^2+y^2+z^2≤2x+4y-6z-14x^2-2x+1+y^2-4y+4+z^2+6z+9≤0(x-1)^2+(y-4)^2+(z+3)^2≤0所以有：x-1=0 得x=1y-4=0 得：y=4z+3=0 得：z=-3x^2+y^2+z^2=1+16+9=26
