已知ab=2 a+b=5 求a^2+b^2和(a-b)^2的值

2024-12-28 06:38:43
推荐回答(3个)
回答1:

a^2+b^2=(a+b)^2-2ab=5^2-2*2=21
(a-b)^2=a^2+b^2-2ab=21-2*2=17

回答2:

a^2+b^2
=a²+2ab+b²-2ab
=(a+b)²-2ab
=2²-2*5
=4-10
=-6

(a-b)²=a²-2ab+b²=a²+b²-2ab=-6-2*5=-16

回答3:

a^2+b^2=(a+b)^2-2ab=21
(a-b)^2=(a+b)^2-4ab=17