已知x눀+4x-1=0,求2x^4+8x대-4x눀-8x+1的值

2024-12-20 04:57:07
推荐回答(2个)
回答1:

2x^4+8x³-4x²-8x+1
=2x²(x²+4x)-4(x²+2x)+1
=2x²(x²+4x-1)-4(x²+4x-1)+2x²+8x-4+1 (注:x²+4x-1=0)
=2x²+8x-3
=2(x²+4x-1)+2-3
= -1

回答2:

-1