计算题 (3⼀3⼀8)^-2⼀3+0.1^-2-(3.14-π)^0+(2⼀1⼀4)^0.5

2024-12-17 05:40:16
推荐回答(5个)
回答1:

你好!

原式= (27/8)^(-2/3) +100 - 1 + √(9/4)
= [(3/2)^3]^(-2/3) + 99 + 3/2
= (3/2)^(-2) + 99+ 1+ 1/2
= 4/9 + 100 + 1/2
= 100 又 17/18

回答2:

(3/3/8)^-2/3+0.1^-2-(3.14-π)^0+(2/1/4)^0.5
=(8/9)^-2/3+100-1+2√2
=(81/64)^1/3+99+2√2
=3/4(三次根号3)+99+3√2

回答3:

好多豆豆哦

回答4:

2.088427

回答5:

看图片。图片上传中...