解二元一次方程组:{2x-1⼀5+3y-2⼀4=2 ,3x+1⼀3-3y+2⼀4=4⼀3

2024-12-16 14:10:02
推荐回答(2个)
回答1:

① 2x-1/5+3y-2/4=2
② 3x+1/3-3y+2/4=4/3
②+① 得:5x-1/5+1/3=2+4/3
5x=16/5
x=16/25
把 x=16/25 代入 ① 32/25-1/5+3y-1/2=2
3y=3/2-27/25 y=7/50

回答2:

:{2x-1/5+3y-2/4=2 ,3x+1/3-3y+2/4=4/3
2x-1/5+3y-2/4=2
4(2x-1)+5(3y-2)=40
8x-4+15y-10=40
8x+15y=54 (1)
3x+1/3-3y+2/4=4/3
4(3x+1)-3(3y+2)=16
12x+4-9y-6=16
12x-9y=18
4x-3y=6 (2)
(1)+(2)*5得
8x+15y+5(4x-3y)=54+6*5
8x+15y+20x-15y=54+30
28x=84
x=3
y=2