noip2003普及组复赛第一题 乒乓球 求助

2024-12-18 05:45:00
推荐回答(1个)
回答1:

if (((x=11)and(x<>y)and(abs(x-y)>=2))or((y=11)and(x<>y)and(abs(x-y)>=2)))
改为if (((x>=11)and(x<>y)and(abs(x-y)>=2))or((y>=11)and(x<>y)and(abs(x-y)>=2)))