(2x²+ax-y+6)-(2bx²-3x+5y-1)
=2x²+ax-y+6-2bx²+3x-5y+1
=(2-2b)x^2+(a+3)x-6y+7
与x值无关,即
2-2b=0,b=1
a+3=0,a=-3
(2x²+ax-y+6)-(2bx²-3x+5y-1)=2x²+ax-y+6-2bx²+3x-5y+1
=(2-2b)x²+(a+3)x-6y+7
因为多项式与X取值无关
∴2-2b=0
a+3=0
∴b=1,a=-3
∴a-2b=-3-2=-5