1. 当x<-3时(x+2)(x-1)^2<=0x+2<=0x<=-2所以，x<-3是，不等式成立2. 当x>-3时且x<>1,(x+2)(x-1)^2>=0x+2>0x>-2因此，不等式的解集是{x|x<-3或者x>=-2,x∈R}
(x+2)(x-1)^2/(x+3)≥0(x+2)(x-1)^2≥0x+2≥0或(x-1)^2≥0x1≥-2，x2≥1
