土木房屋建筑学题:某三层中学楼,二级防火,内廊式,每层人数300人,请设计该教学楼的走道宽度。要过程!

要过程和思路!
2025-03-25 00:21:47
推荐回答(4个)
回答1:

首先《中小学建筑规范》规定:教学楼走道的净宽度应符合下列规定:教学用房:内廊不应小于2100mm;外廊不应小于1800mm。
二是《建筑设计防火规范》规定,教学楼走廊宽度按地上一、二层0.65m/百人,地上三层0.75m/百人计算,所以一、二层走廊宽度3X0.65=1.95m,三层3x0.75=2.25m。
综合上述两条,一、二层走廊净宽度至少2.1m,三层至少2.25m。

回答2:

看看这个吧,关键是计算人流量的,结合房屋建筑学的课本上的规定,做到2700的话,减去柱子的宽度(暂时)定为400吧,净宽为2300。对中学来讲,满足了。。要考虑单、双股人流的。。。我这没法查,你自己搞定吧,这个很简单啊。。。

回答3:

根据最新的《中小学设计规范》,教学用房的内走道净宽度不应小于2.4m,单侧走道及外廊的净宽度不应小于1.8m
地上一、二层的每100人的净宽度是0.7m,地上三层是0.8m
因此,地上一、二层的走道宽度是0.7*3=2.1m,地上三层是0.8*3=2.4m。
综合上述两条,一、二层走廊净宽度至少是2.4m,三层同样至少2.4m。

回答4:

清查建筑设计防火规范我记得好像是3层的是每百人0.7米。3x0.7=2.1米

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