230问答网 > 飞机起飞时要先在跑道上滑行一段路程这种运动在物理上叫匀加速直线运动其公式为s=2分之1at

飞机起飞时要先在跑道上滑行一段路程这种运动在物理上叫匀加速直线运动其公式为s=2分之1at

2025-03-24 11:39:40
推荐回答（2个）
回答1：

。。。你自己不都把公式列出来了么。。代进去算不就得了。。。
4000=1/2 * 20* t平方 t=20s
v1=0+20*20=400m/s

回答2：

S=1/2at*t.S=4000,a=20m/(s*s).代入公式求的t=20s.起飞的速度为。V0=at=20m/(s*s)×20s=400m/s.
滑行所用的时间是20s
起飞的速度为400m/s

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