(1/2)^[log2(3)]
=[2^(-1)]^[log2(3)]
=2^[(-1)*log2(3)]
=2^[-log2(3)]
=2^[log2(3)^(-1)]
=2^[log2(1/3)]
(1/2)log2底3=2^-1log2底3=2log2底3^-1=2log2底1/3有点难打啊，我已经尽力了。
