解不等式(x+2)(x+1)^2(x-1)(x-2)<=0

2024-12-23 06:13:02
推荐回答(2个)
回答1:

(x+1)^2>=0
所以(x+2)(x-1)(x-2)<=0
零点是-2,1,2
所以x<=-2,1<=x<=2

回答2:

用标根法,有:
1≤x≤2,或-2≤x≤-1