推荐回答(5个)
1.设C车装货物 X 千克 , 由题得 B=2X , A=2X+160 , A=4X 即 4X=2X+160
得 X=80 所以 C=80() B=160 , A=320 —共A+B+C=560(千克)
2.设乙为 X , 则甲为 2X ,丙为 X-240
又因为 三个筑路队共筑路1360米 得 X + 2X +(X-240)=1360 解得 X=400
得甲队筑 800 米,乙队 400 米,丙队160 米
3.设原来两根铁丝为 X 厘米, 由题得 X-18=3(X-26)解方程的 X=30
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1.有A、B、C三辆车,C车装的货物是B车的一半,B车比A车少160千克,A车装的是C车的4倍,A、B、C三辆车共装货物多少千克
设c车装的x千克,(2x+160)÷x=4 ,2x+160=4x,160=4x-2x,160=2x ,x=80
既然c等于80,那b就等于80x2=160千克,a就等于160+160=320千克。
2.三个筑路队共筑路1360米,甲队筑的米数是乙队的2倍,乙队比丙队多240米,三个队各筑多少米
设丙队为x米,x+(x+240)+(x+240)x2=1360,x+x+240+2x+480=1360,4x+720=1360,4x=640,x=160. 乙=160+240=400. 甲=400x2=800
3.两根同样长的铁丝,第一根剪去18厘米,第二根剪去26厘米,余下的铁丝第一根是第二根的3倍。原来两根铁丝各长多少厘米
设第一根铁丝为x米,(x-18)÷3=x-26,x-18=(x-26)x3,x-18=3x-78,x=3x-60,60=2x,x=30
4.被除数、除数、商三个数的和是212,已知商是2,被除数和除数各是多少?
被除数=2除数,212÷2=106,被除数等于106,106÷2=53=除数
5.甲、乙两个仓库共有大米800袋,如果从甲仓库取出25袋放到乙仓库中,则甲仓库比乙仓库还多8袋,求两个仓库原来各有多少袋大米
设乙为x,800-x-25-8=x,800-2x=25+8,800-2x=33,800-33=2x,x=767÷2,x=383.5
6.爸爸今年43岁,儿子今年11岁,几年后爸爸的年龄是二字的3倍
设x年后,爸爸的年龄是儿字的3倍,x+43=(x+11)x3,解得x=5
7.三个植树队植树1900棵,甲队植树的棵树是乙队的2倍,乙队比丙队少植300棵,三个队各植了多少棵
设乙为x棵,2x+x+300+x=1900,解得x=400,甲=400x2=800,丙=400+300=700
8.甲、乙、丙三数的和是78,甲数比乙数的2倍多4,乙数比丙数的3倍少2,求这三个数
设丙为x,x+3x-2+(3x-2)x2+4=78,解得x为8,乙就是22,甲48.丙就是8
9.两篮鸡蛋共19只,若甲篮再放入4只,乙篮中取出2只,这种乙篮比甲篮鸡蛋还多1只,求甲、乙两篮原来各有多少只鸡蛋
设甲篮x只 X+4= 19-X-2-1 解得x等于6 乙就等于19-6=13
10.小东的图书中有58本不是故事书,有42本不是科技书,小东的故事书和科技书共有60本,小东科技书有多少本书
设小东一共有x本书,x-58+x-42=60,解得x等于80.
11.面值10元的面值5元的钞票若干张,共175元。10元的张数是5元张数的3倍,这两种钞票各几张
设五元的x张。10x3x+5x=175,解得x=5,那十元的就有5x3=15张了!
我打那么累,希望能够帮到你,也给我一个最佳答案,谢谢!O(∩_∩)O哈哈~
1、根据题意C=B/2 .B=A-160,A=4C。得A=2B,再得B=160。所以A=320,C=80. A+B+C=560。 2、设乙筑x米。则甲是2x,丙是x-240。2x+x+x-240=1360.x=400,所以甲=800,丙=160。 3、设第二根绳剩下x米。因为两根绳一样长,所以18+3x=26+x. x=4.原长=26+4=30,两根一样。 4.设除数是x.则被除数是2x.有2x+x=212-2。除数x=70 被除数=140。 5.这题画图就好。甲比乙多25*2+8=58,乙有(800-58)÷2=371,甲有371+58=429。 6、设过x年后。(43+x)/(11+x)=3,x=5 7、设乙种x棵。2x+x+x+300=1900. 乙x=400,甲2x=800,丙x+300=700. 8.设乙为x。2x+4+x+3x+2=78 x=12 甲=2*12+4=28 丙=3*12+2=38。9、设甲x只。乙比甲多4+2+1=7。x+x+7=19. X=6, 甲是13. 10、设五元的x张。10*3x+5x=175 x=5。 十元的15张。
a是c的4倍,b是c的2倍,所以a是b的2倍。因为b车比a车少160千克,所以a是320千克,b是160千克,c是80千克,一共560千克。
我是上面的 ♀微微的微笑。不好意思,刚第十题是最后一题,现在给你第十题的答案。 这题最好画图,他有科技书、故事书、其它书,58+42+60,你会发现是这三本书各加了两次,那么(58+42+60)÷2=80是他有书的总数,80-42=38本,便是科技书的数目! 呵呵,我手机的啊,打字累啊~如果采纳的话,就请采纳 ♀微微的微笑 的回答! 可以吗? 谢谢!
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